x^2(x+2)+4x(x+2)+3(x+2)=0

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Solution for x^2(x+2)+4x(x+2)+3(x+2)=0 equation: 


Simplifying
x2(x + 2) + 4x(x + 2) + 3(x + 2) = 0

Reorder the terms:
x2(2 + x) + 4x(x + 2) + 3(x + 2) = 0
(2 * x2 + x * x2) + 4x(x + 2) + 3(x + 2) = 0
(2x2 + x3) + 4x(x + 2) + 3(x + 2) = 0

Reorder the terms:
2x2 + x3 + 4x(2 + x) + 3(x + 2) = 0
2x2 + x3 + (2 * 4x + x * 4x) + 3(x + 2) = 0
2x2 + x3 + (8x + 4x2) + 3(x + 2) = 0

Reorder the terms:
2x2 + x3 + 8x + 4x2 + 3(2 + x) = 0
2x2 + x3 + 8x + 4x2 + (2 * 3 + x * 3) = 0
2x2 + x3 + 8x + 4x2 + (6 + 3x) = 0

Reorder the terms:
6 + 8x + 3x + 2x2 + 4x2 + x3 = 0

Combine like terms: 8x + 3x = 11x
6 + 11x + 2x2 + 4x2 + x3 = 0

Combine like terms: 2x2 + 4x2 = 6x2
6 + 11x + 6x2 + x3 = 0

Solving
6 + 11x + 6x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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